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Bash-5.3 distribution sources and documentation
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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#
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# change behavior of shell builtins to extend assoc_expand_once to indexed
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# arrays
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export subscript='$(echo INJECTION! >&2 ; echo 0)'
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shopt -s array_expand_once
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printf -v a["$subscript"] %s hi
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declare -p a
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unset a
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printf -v "a[$subscript]" %s hi
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declare -p a
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a[0]=hi
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unset a["$subscript"]
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declare -p a
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unset a
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unset a["$subscript"]
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declare -p a
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unset -v a
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read a["$subscript"] <<<hi
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declare -p a
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declare -a a
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read a["$subscript"] <<<hi
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declare -p a
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unset -v a
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declare -a a
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{ sleep 1; exit 12; } & bgpid=$!
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wait -n -p a["$subscript"] $bgpid
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declare -p a
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unset -v a
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declare -a a
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declare -i a["$subscript"]=42
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declare -p a
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# this still won't work because the quotes prevent it from being recognized as
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# an assignment statement
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#declare -i "a[$subscript]"=42
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#declare -p a
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test -v a["$subscript"] && echo set
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[ -v a["$subscript"] ] && echo set
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let a["$subscript"]+=1
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unset -v a
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# these are all already arithmetic expression errors
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declare -a a
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(( a[$subscript]++ ))
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declare -p a
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: $(( a[$subscript]++ ))
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declare -p a
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a[$subscript]=hi
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declare -p a
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# length shortcuts for unset variables, so give it a value
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a[0]=zero
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echo ${#a[$subscript]}
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unset -v a
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# compound assignments should not perform double expansion
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a=( [$subscript]=hi )
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declare -p a
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declare -a a
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a=( [$subscript]=hi )
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declare -p a
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unset -v a
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