Files
Jungfraujoch/reader/SweepLayout.cpp
T
leonarski_fandClaude Opus 5 5c6dedea71 Do not read the oscillation width as the rotation step
SweepLayout rejected any inter-frame difference below half the header's
oscillation width as read-back jitter. A series that steps by less than
it exposes - overlapping wedges, or a writer that puts the whole sweep's
range in that field - then had every difference rejected, no step was
found, and the files fell into the "series that never turns" branch,
which lays them out end to end and, unlike the gapped path, said
nothing. The jitter bound is now absolute (1e-4 deg, below any step an
instrument makes and above 32-bit float read-back noise), and the
end-to-end fallback warns when the angles do span a rotation.

Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_013nW6FNRP1bBJJ8pfHiByAT
2026-09-20 18:59:59 +02:00

285 lines
15 KiB
C++

// SPDX-FileCopyrightText: 2026 Filip Leonarski, Paul Scherrer Institute <filip.leonarski@psi.ch>
// SPDX-License-Identifier: GPL-3.0-only
#include "SweepLayout.h"
#include <algorithm>
#include <cmath>
#include <cctype>
#include <filesystem>
#include <optional>
#include "../common/JFJochException.h"
#include "../common/Logger.h"
namespace {
// The difference between two recorded angles, brought into (-180, 180]. A sweep that runs past 360
// starts over at 0 in some writers' headers and keeps counting in others', and this reads both the
// same way. Safe because no gap seen in a deposited series comes close to half a turn - the widest
// in the corpus here is 0.7 degrees - so a folded step is the step and not an aliased one.
double Fold(double d) {
while (d <= -180.0) d += 360.0;
while (d > 180.0) d -= 360.0;
return d;
}
std::string Name(const std::string &path) {
return std::filesystem::path(path).filename().string();
}
// The frame number a file name ends in. Every one-file-per-image format here numbers its frames that
// way, and the numbering is a second, independent statement of how long the series should be: a
// directory holding fewer files than its own numbering spans is a directory that was not unpacked
// whole, which is worth saying out loud - one staged sweep here was short by 690 frames for months,
// and the only sign of it was a resolution nobody could explain.
std::optional<int64_t> TrailingNumber(const std::string &path) {
const std::string name = Name(path);
size_t end = name.find_last_of('.');
if (end == std::string::npos)
end = name.size();
// ".cbf.gz" and the like: step back over as many trailing extensions as there are.
while (end > 0 && !std::isdigit(static_cast<unsigned char>(name[end - 1]))) {
const size_t dot = name.find_last_of('.', end - 1);
if (dot == std::string::npos)
return {};
end = dot;
}
size_t begin = end;
while (begin > 0 && std::isdigit(static_cast<unsigned char>(name[begin - 1])))
begin--;
if (begin == end)
return {};
return std::stoll(name.substr(begin, end - begin));
}
// The first few frames of a list, by name, for a message a user has to act on. All of them would be
// hundreds of lines on the series this exists for.
std::string NameSome(const std::vector<std::string> &paths) {
const size_t show = std::min<size_t>(paths.size(), 5);
std::string out;
for (size_t i = 0; i < show; i++)
out += (i ? ", " : "") + Name(paths[i]);
if (paths.size() > show)
out += fmt::format(" and {} more", paths.size() - show);
return out;
}
// Whether two readings of the same instrument setting are the same reading. Relative, because what
// counts as the same distance depends on the distance; the bounds are far wider than a read-back
// jitters and far narrower than a real move.
bool Same(double a, double b, double rel_tol, double abs_tol) {
return std::abs(a - b) <= std::max(abs_tol, rel_tol * std::max(std::abs(a), std::abs(b)));
}
} // namespace
namespace sweep {
Layout Place(const std::vector<Frame> &frames, const std::string &logger_name) {
if (frames.empty())
throw JFJochException(JFJochExceptionCategory::InputParameterInvalid,
"No images to place on a sweep");
Logger logger(logger_name);
// ---- one sweep, or several sets of images that happen to share a name?
//
// Everything below takes the geometry from the first frame and applies it to all of them, so a
// series whose headers disagree about where the detector was is not a sweep at all and must not
// be silently averaged into one. A folder of screening shots is the case that matters: it fails
// deep inside indexing, as a lattice nobody can explain, when it should fail here by name.
const Frame &f0 = frames[0];
std::vector<std::string> bad_distance, bad_beam, bad_wavelength, bad_increment;
for (const auto &f : frames) {
if (!Same(f.distance_m, f0.distance_m, 0.005, 1e-6))
bad_distance.push_back(f.path);
if (std::abs(f.beam_x_px - f0.beam_x_px) > 2.0 || std::abs(f.beam_y_px - f0.beam_y_px) > 2.0)
bad_beam.push_back(f.path);
if (!Same(f.wavelength_A, f0.wavelength_A, 0.001, 1e-9))
bad_wavelength.push_back(f.path);
if (!Same(f.increment_deg, f0.increment_deg, 0.01, 1e-6))
bad_increment.push_back(f.path);
}
const auto refuse = [&](const char *what, const std::vector<std::string> &who, double first) {
throw JFJochException(JFJochExceptionCategory::InputParameterInvalid,
fmt::format("The images named here are not one sweep: {} differ(s) from "
"{} ({:g}) in {}. Process the sweeps separately.",
what, Name(f0.path), first, NameSome(who)));
};
if (!bad_distance.empty()) refuse("the detector distance", bad_distance, f0.distance_m);
if (!bad_beam.empty()) refuse("the beam centre", bad_beam, f0.beam_x_px);
if (!bad_wavelength.empty()) refuse("the wavelength", bad_wavelength, f0.wavelength_A);
if (!bad_increment.empty()) refuse("the oscillation width", bad_increment, f0.increment_deg);
// ---- the angles, unwrapped so a sweep that passes 360 keeps counting
std::vector<double> angle(frames.size());
angle[0] = f0.angle_deg;
for (size_t i = 1; i < frames.size(); i++)
angle[i] = angle[i - 1] + Fold(frames[i].angle_deg - angle[i - 1]);
// ---- a first guess at the rotation step
//
// The smallest move between two frames that ARE adjacent in the series, signed with the way it
// went. Taking the FIRST pair instead - which is what this code used to do - reads a gap as the
// step and compresses the whole sweep by however much is missing. The header's own
// Angle_increment is not used for this: it is the oscillation WIDTH, which a series with
// overlapping or spaced wedges does not step by.
//
// A difference below this is jitter in the recorded angle rather than a step, and taking one as
// the step would spread the sweep over millions of slots. The bound is ABSOLUTE and far below
// any move an instrument makes: these headers write their angles as 32-bit floats, which is a
// few parts in 100000 - under 1e-4 deg even at 360 - while the finest rotation step collected is
// a thousandth of a degree. Deriving it from the oscillation width instead, as this used to, is
// the same mistake the paragraph above warns of: a series with overlapping wedges steps by far
// less than it exposes, and some writers put the whole sweep's range in that field, so every
// inter-frame difference was rejected, the guess stayed zero and a turning series fell into the
// "never turns" branch below and was laid out end to end.
//
// It is only a guess, and deliberately the crudest one: a single recorded difference, and the
// one biased furthest low by the read-back noise. It is used below to count STEPS between
// neighbours, never to place a frame outright.
constexpr double too_fine = 1e-4; // degrees
double guess = 0;
for (size_t i = 1; i < frames.size(); i++) {
const double d = Fold(angle[i] - angle[i - 1]);
if (std::abs(d) > std::max(too_fine, 1e-6) && (guess == 0 || std::abs(d) < std::abs(guess)))
guess = d;
}
Layout out;
// A series that never turns: a grid scan, a set of stills, or a single image. There is no sweep
// to place anything on, so the files are the slots and the header's nominal increment stands.
if (guess == 0) {
// ... unless the angles say it DOES turn, over the series if never between two neighbours.
// Then this layout is a guess - the files end to end, at the nominal increment - and it has
// to say so, as the gapped path below does. Nothing else in this branch reports anything.
const double turned = std::abs(angle.back() - angle[0]);
if (turned > std::max(std::abs(f0.increment_deg), 1e-3))
logger.Warning("The angles of these {} images span {:.4f} deg, but no two neighbours are "
"more than {:g} deg apart, so no rotation step can be read from them. They "
"are laid out one after another at the header's {:.4f} deg - check that "
"this is the sweep the files describe.",
frames.size(), turned, too_fine, f0.increment_deg);
out.files.reserve(frames.size());
for (const auto &f : frames)
out.files.push_back(f.path);
out.start_deg = f0.angle_deg;
out.increment_deg = f0.increment_deg;
out.present = frames.size();
return out;
}
// ---- how many steps apart each pair of NEIGHBOURS is
//
// Counted from one local difference at a time, so nothing accumulates: a recorded angle carries
// a few parts in 100000 of read-back noise (these headers are written from 32-bit floats), which
// is nowhere near half a step for one pair however long the sweep is. Measuring the frame's
// position against the FIRST frame instead multiplies that noise by the frame number - on a 2700
// frame sweep the guess above was 1.3e-4 low and by frame 1924 the drift had reached a quarter
// of a step, so a perfectly regular series was refused as scattered.
//
// This is also what carries a sweep past a full turn. Each fold is one step forward, so the
// count keeps climbing through 360 and a frame taken on the second revolution lands beyond the
// first, not on top of it. A series that genuinely jumps BACK - two sweeps of one crystal
// concatenated - folds to a large negative count in a single pair and collides below.
std::vector<int64_t> slot(frames.size());
slot[0] = 0;
for (size_t i = 1; i < frames.size(); i++)
slot[i] = slot[i - 1] + std::llround(Fold(angle[i] - angle[i - 1]) / guess);
// ---- the step the whole series agrees on
//
// A straight line through (steps, angle): every frame's own header has a say, so the read-back
// noise averages out instead of one unlucky pair setting the scale for thousands of frames.
double mean_slot = 0, mean_angle = 0;
for (size_t i = 0; i < frames.size(); i++) {
mean_slot += static_cast<double>(slot[i]);
mean_angle += angle[i];
}
mean_slot /= static_cast<double>(frames.size());
mean_angle /= static_cast<double>(frames.size());
double cov = 0, var = 0;
for (size_t i = 0; i < frames.size(); i++) {
const double ds = static_cast<double>(slot[i]) - mean_slot;
cov += ds * (angle[i] - mean_angle);
var += ds * ds;
}
// Two frames a step apart give var > 0; var == 0 only if every frame landed on one step, which
// the guess above has already ruled out.
const double step = var > 0 ? cov / var : guess;
const double start = mean_angle - step * mean_slot;
// ---- every frame on that step, or this is not a rotation series
std::vector<std::string> off_grid;
for (size_t i = 0; i < frames.size(); i++)
if (std::abs(angle[i] - (start + step * static_cast<double>(slot[i]))) > 0.25 * std::abs(step))
off_grid.push_back(frames[i].path);
if (!off_grid.empty())
throw JFJochException(JFJochExceptionCategory::InputParameterInvalid,
fmt::format("The images named here do not lie on one rotation series: "
"{} starts at {:.4f} deg, the series steps by {:.4f} deg, "
"and {} sit(s) off that step. Screening images taken at "
"scattered angles are not a sweep.",
Name(f0.path), angle[0], step, NameSome(off_grid)));
// ---- the slots
//
// Numbered from the frame that comes FIRST on the spindle, which is not always the first file:
// slot 0 is where the goniometer's start angle is, and the files were only ever sorted by name.
const int64_t first = *std::min_element(slot.begin(), slot.end());
const int64_t last = *std::max_element(slot.begin(), slot.end());
out.files.assign(static_cast<size_t>(last - first) + 1, std::string());
std::vector<std::string> duplicates;
for (size_t i = 0; i < frames.size(); i++) {
std::string &at = out.files[static_cast<size_t>(slot[i] - first)];
if (!at.empty())
duplicates.push_back(frames[i].path);
at = frames[i].path;
}
// A sweep of more than one full turn reaches the same recorded angle again and is NOT this: it
// gets there by stepping forward the whole way, so its second revolution occupies fresh slots.
// What collides here is a series that jumped back - two sweeps of one crystal concatenated.
if (!duplicates.empty())
throw JFJochException(JFJochExceptionCategory::InputParameterInvalid,
fmt::format("The images named here go back to a point of the rotation "
"an earlier image of the series already took: {}. Two "
"sweeps of the same crystal have to be processed "
"separately.",
NameSome(duplicates)));
out.start_deg = start + step * static_cast<double>(first);
out.increment_deg = step;
out.present = frames.size();
if (out.present < out.files.size())
logger.Warning("{} of the {} images the sweep spans are present; the {} missing ones are "
"left as gaps, so every image keeps the spindle angle its own header states "
"({:.2f} to {:.2f} deg). The merge will be that much less complete.",
out.present, out.files.size(), out.files.size() - out.present,
out.start_deg,
out.start_deg + step * static_cast<double>(out.files.size() - 1));
// The numbering says the same thing a second way, and says it about the ends of the series too,
// which the angles cannot: a sweep missing its first and last frames still spans only the angles
// that are there. Where the two disagree with the file count, the directory is short.
int64_t lo = 0, hi = 0;
bool numbered = true;
for (size_t i = 0; i < frames.size() && numbered; i++) {
const auto n = TrailingNumber(frames[i].path);
if (!n.has_value())
numbered = false;
else if (i == 0)
lo = hi = *n;
else
lo = std::min(lo, *n), hi = std::max(hi, *n);
}
if (numbered && hi - lo + 1 > static_cast<int64_t>(out.present))
logger.Warning("The file numbering runs {}..{}, which is {} frames, but the directory holds "
"{}: {} are not there. If this series should be complete, it was not unpacked "
"or copied whole - check the source.",
lo, hi, hi - lo + 1, out.present, hi - lo + 1 - static_cast<int64_t>(out.present));
return out;
}
} // namespace sweep