zebra/pyzebra
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Infer path of file with version from path of release script

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usov_i 2024-11-19 15:26:56 +01:00
parent 60f01d9dd8
commit e5030902c7
1 changed files with 4 additions and 4 deletions
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8
make_release.py
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@ -12,13 +12,13 @@ def main():
print("Aborting, not on 'main' branch.")
return
filepath = "pyzebra/__init__.py"
version_filepath = os.path.join(os.path.basename(os.path.dirname(__file__)), "__init__.py")
parser = argparse.ArgumentParser()
parser.add_argument("level", type=str, choices=["patch", "minor", "major"])
args = parser.parse_args()
with open(filepath) as f:
with open(version_filepath) as f:
file_content = f.read()
version = re.search(r'__version__ = "(.*?)"', file_content).group(1)
@ -36,10 +36,10 @@ def main():
new_version = f"{major}.{minor}.{patch}"
with open(filepath, "w") as f:
with open(version_filepath, "w") as f:
f.write(re.sub(r'__version__ = "(.*?)"', f'__version__ = "{new_version}"', file_content))
os.system(f"git commit {filepath} -m 'Updating for version {new_version}'")
os.system(f"git commit {version_filepath} -m 'Updating for version {new_version}'")
os.system(f"git tag -a {new_version} -m 'Release {new_version}'")