The peak nearest the given cell could be a single stray frame when the given cell is a few percent off the crystal (a cryo cell given for room-temperature lysozyme stills): the run then merged one frame. Every population is now found from its own peak and valleys, and of those holding at least a tenth of the frames the one centred nearest the given cell is kept. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
97 lines
4.3 KiB
C++
97 lines
4.3 KiB
C++
// SPDX-FileCopyrightText: 2026 Filip Leonarski, Paul Scherrer Institute <filip.leonarski@psi.ch>
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// SPDX-License-Identifier: GPL-3.0-only
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#include "CellPopulation.h"
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#include <algorithm>
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#include <cmath>
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#include <limits>
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std::pair<double, double> GivenCellPopulation(const std::vector<double> &relative_volume) {
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constexpr double everything = std::numeric_limits<double>::infinity();
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// Below this many frames a histogram has no valleys to speak of.
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constexpr size_t MIN_FRAMES = 50;
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// A valley separates two populations only where it dips below this fraction of the kept peak; a
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// shallower dip is noise in one population's tail.
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constexpr double VALLEY_FRACTION = 0.5;
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// A population holding less than this share of the frames is a stray group, not a crystal form.
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constexpr double MIN_SHARE = 0.1;
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const size_t n = relative_volume.size();
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if (n < MIN_FRAMES)
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return {-everything, everything};
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std::vector<double> v = relative_volume;
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std::sort(v.begin(), v.end());
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// The bin: twice a robust standard deviation over n^(1/3) (Freedman-Diaconis with the median
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// absolute deviation in place of the interquartile range, which a second population inflates).
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const double median = v[n / 2];
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std::vector<double> dev(n);
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for (size_t i = 0; i < n; i++)
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dev[i] = std::fabs(v[i] - median);
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std::nth_element(dev.begin(), dev.begin() + n / 2, dev.end());
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const double bin = 2.0 * 1.4826 * dev[n / 2] / std::cbrt(static_cast<double>(n));
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if (!(bin > 0))
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return {-everything, everything};
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const double lo = v.front();
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const int nbins = static_cast<int>((v.back() - lo) / bin) + 1;
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std::vector<double> count(nbins, 0.0);
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for (double x : v)
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count[std::min(nbins - 1, static_cast<int>((x - lo) / bin))] += 1.0;
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// Three-bin running mean, so a single empty or full bin is not a valley or a peak.
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std::vector<double> smooth(nbins, 0.0);
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for (int i = 0; i < nbins; i++) {
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const int a = std::max(0, i - 1), b = std::min(nbins - 1, i + 1);
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double s = 0;
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for (int j = a; j <= b; j++)
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s += count[j];
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smooth[i] = s / (b - a + 1);
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}
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// Out from a peak on each side: the valley is the lowest point, below VALLEY_FRACTION of the peak,
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// before the histogram rises again to twice its height by more than counting noise - the next
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// population, however small. None: the population runs out to the end of the data.
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const auto valley = [&](int peak, int step) {
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int lowest = peak;
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for (int i = peak + step; i >= 0 && i < nbins; i += step) {
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if (smooth[i] < smooth[lowest])
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lowest = i;
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const double low = smooth[lowest], here = smooth[i];
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// A three-bin mean of Poisson counts has a variance of a third of its value.
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const bool rises = here >= 2.0 * low && here - low > 3.0 * std::sqrt((here + low) / 3.0);
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if (low < VALLEY_FRACTION * smooth[peak] && rises)
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return lowest;
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}
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return -1;
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};
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// Every population: a local maximum of the histogram and the valleys about it. Of those that hold
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// a real share of the frames, the one centred nearest the given cell is kept - not merely the peak
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// nearest it, which can be a few stray frames when the given cell is a percent off the crystal.
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double best_low = -everything, best_high = everything, best_distance = everything;
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for (int i = 0; i < nbins; i++) {
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if (smooth[i] <= 0 || (i > 0 && smooth[i - 1] > smooth[i]) || (i + 1 < nbins && smooth[i + 1] >= smooth[i]))
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continue;
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const int left = valley(i, -1), right = valley(i, +1);
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const double low = left < 0 ? -everything : lo + (left + 0.5) * bin;
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const double high = right < 0 ? everything : lo + (right + 0.5) * bin;
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size_t count = 0;
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double sum = 0;
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for (double x : v)
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if (x >= low && x <= high) {
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count++;
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sum += x;
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}
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if (count < MIN_SHARE * static_cast<double>(n))
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continue;
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const double distance = std::fabs(sum / static_cast<double>(count));
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if (distance < best_distance) {
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best_distance = distance;
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best_low = low;
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best_high = high;
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}
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}
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return {best_low, best_high};
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}
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