A candidate can have several confirmed subgroups of the same order - 422 has
both 4 and 222 - and on a twinned crystal the rival is not a harmless
alternative: a P4 crystal twinned by 2[100] has 222 confirmed too, and 222
CONTAINS the twin laws, so its own merge b is already ballooned. The H test
already answers to every tied parent; the systematic-b veto and rescue took
whichever one the enumeration happened to list first (222 before 4, by space-
group number), which disabled the veto on exactly the case it exists for. Take
the smallest parent b, which is the conservative direction for both tests.
The refusal message also quoted the raw parent b rather than the floored value
the veto actually compared against.
Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
leonarski_fandClaude Opus 5
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