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<H2><A NAME="SECTION00622000000000000000"></A><A NAME="sec:11"></A>
<BR>
Basic binning
</H2>
<P>
<DL COMPACT>
<DT>1. </DT>
<DD>
We have several patterns, say <IMG
WIDTH="17" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img72.png"
ALT="$ P$">
. Each <IMG
WIDTH="13" HEIGHT="15" ALIGN="BOTTOM" BORDER="0"
SRC="img73.png"
ALT="$ k$">
-th pattern, for <!-- MATH
$k=1,\ldots,P$
-->
<IMG
WIDTH="90" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img74.png"
ALT="$ k=1,\ldots,P$">
, is
constituted by <IMG
WIDTH="25" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img75.png"
ALT="$ N_k$">
angular intervals in the diffraction angle <!-- MATH
$2\theta\equiv{\ensuremath{{2\theta}}}$
-->
<IMG
WIDTH="57" HEIGHT="15" ALIGN="BOTTOM" BORDER="0"
SRC="img76.png"
ALT="$ 2\theta\equiv{\ensuremath{{2\theta}}}$">
:
<P><!-- MATH
\begin{displaymath}
b_{k,j}={\ensuremath{\left[{{\ensuremath{{2\theta}}}_{k,j}^{-},{\ensuremath{{2\theta}}}_{k,j}^{+}}\right]}},\qquad j=1,\ldots,N_k
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="270" HEIGHT="45" ALIGN="MIDDLE" BORDER="0"
SRC="img77.png"
ALT="$\displaystyle b_{k,j}={\ensuremath{\left[{{\ensuremath{{2\theta}}}_{k,j}^{-},{\ensuremath{{2\theta}}}_{k,j}^{+}}\right]}},\qquad j=1,\ldots,N_k
$">
</DIV><P>
</P>
of center
<P><!-- MATH
\begin{displaymath}
\hat{b}_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{{\ensuremath{{2\theta}}}_{k,j}^{+}+{\ensuremath{{2\theta}}}_{k,j}^{-}}}}}{{\ensuremath{\displaystyle{2}}}}}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="140" HEIGHT="62" ALIGN="MIDDLE" BORDER="0"
SRC="img78.png"
ALT="$\displaystyle \hat{b}_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\disp...
...{+}+{\ensuremath{{2\theta}}}_{k,j}^{-}}}}}{{\ensuremath{\displaystyle{2}}}}}}}
$">
</DIV><P>
</P>
and width
<P><!-- MATH
\begin{displaymath}
{\ensuremath{\left|{b_{k,j}}\right|}}={\ensuremath{{2\theta}}}_{k,j}^{+}-{\ensuremath{{2\theta}}}_{k,j}^{-}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="145" HEIGHT="36" ALIGN="MIDDLE" BORDER="0"
SRC="img79.png"
ALT="$\displaystyle {\ensuremath{\left\vert{b_{k,j}}\right\vert}}={\ensuremath{{2\theta}}}_{k,j}^{+}-{\ensuremath{{2\theta}}}_{k,j}^{-}
$">
</DIV><P>
</P>
To each interval is associated a counting <IMG
WIDTH="33" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img80.png"
ALT="$ C_{k,j}$">
, an efficiency correction factor <IMG
WIDTH="29" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img81.png"
ALT="$ e_{k,j}$">
, a
monitor <IMG
WIDTH="36" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img82.png"
ALT="$ m_{k,j}$">
(ionization chamber times acquisition time). All 'bad' intervals have been already flagged down and discarded.
Efficiency corrections and monitors are supposed to be normalized to a suitable value.
Note that intervals <IMG
WIDTH="29" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img83.png"
ALT="$ b_{k,j}$">
might have multiple overlaps and might not cover an compact angular
range.
</DD>
<DT>2. </DT>
<DD>Following Mighell's statistics[6] and normal scaling procedures, we first
transform those numbers into associated intensities, intensity rates and relevant s.d.:
<P><!-- MATH
\begin{displaymath}
I_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{e_{k,j}}}}}{{\ensuremath{\displaystyle{m_{k,j}}}}}}}}{\ensuremath{\left({C_{k,j}+\min{\ensuremath{\left({1,C_{k,j}}\right)}}}\right)}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="232" HEIGHT="45" ALIGN="MIDDLE" BORDER="0"
SRC="img84.png"
ALT="$\displaystyle I_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaysty...
...nsuremath{\left({C_{k,j}+\min{\ensuremath{\left({1,C_{k,j}}\right)}}}\right)}}
$">
</DIV><P>
</P>
<P><!-- MATH
\begin{displaymath}
\sigma_{I_{k,j}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{e_{k,j}}}}}{{\ensuremath{\displaystyle{m_{k,j}}}}}}}}\sqrt{{\ensuremath{\left({C_{k,j}+1}\right)}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="177" HEIGHT="50" ALIGN="MIDDLE" BORDER="0"
SRC="img85.png"
ALT="$\displaystyle \sigma_{I_{k,j}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\d...
...ath{\displaystyle{m_{k,j}}}}}}}}\sqrt{{\ensuremath{\left({C_{k,j}+1}\right)}}}
$">
</DIV><P>
</P>
<P><!-- MATH
\begin{displaymath}
r_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{I_{k,j}}}}}{{\ensuremath{\displaystyle{{\ensuremath{\left|{b_{k,j}}\right|}}}}}}}}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{e_{k,j}}}}}{{\ensuremath{\displaystyle{m_{k,j}{\ensuremath{\left|{b_{k,j}}\right|}}}}}}}}}{\ensuremath{\left({C_{k,j}+\min{\ensuremath{\left({1,C_{k,j}}\right)}}}\right)}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="323" HEIGHT="53" ALIGN="MIDDLE" BORDER="0"
SRC="img86.png"
ALT="$\displaystyle r_{k,j}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaysty...
...nsuremath{\left({C_{k,j}+\min{\ensuremath{\left({1,C_{k,j}}\right)}}}\right)}}
$">
</DIV><P>
</P>
<P><!-- MATH
\begin{displaymath}
\sigma_{r_{k,j}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{\sigma_{I_{k,j}}}}}}{{\ensuremath{\displaystyle{{\ensuremath{\left|{b_{k,j}}\right|}}}}}}}}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{e_{k,j}}}}}{{\ensuremath{\displaystyle{{\ensuremath{\left|{b_{k,j}}\right|}}m_{k,j}}}}}}}}\sqrt{{\ensuremath{\left({C_{k,j}+1}\right)}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="269" HEIGHT="50" ALIGN="MIDDLE" BORDER="0"
SRC="img87.png"
ALT="$\displaystyle \sigma_{r_{k,j}}={\ensuremath{\displaystyle{\frac{{\ensuremath{\d...
...k,j}}\right\vert}}m_{k,j}}}}}}}}\sqrt{{\ensuremath{\left({C_{k,j}+1}\right)}}}
$">
</DIV><P>
</P>
</DD>
<DT>3. </DT>
<DD>
We set up the final binned grid,
composed of <IMG
WIDTH="22" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img88.png"
ALT="$ M$">
binning intervals
<P><!-- MATH
\begin{displaymath}
B_\ell=[{\ensuremath{{2\theta}}}_0+(\ell-1)B, {\ensuremath{{2\theta}}}_0+\ell B],\qquad \ell=1,\ldots,M
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="351" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img89.png"
ALT="$\displaystyle B_\ell=[{\ensuremath{{2\theta}}}_0+(\ell-1)B, {\ensuremath{{2\theta}}}_0+\ell B],\qquad \ell=1,\ldots,M
$">
</DIV><P>
</P>
all contiguous and each having the same width <P><!-- MATH
\begin{displaymath}
{\ensuremath{\left|{B_\ell}\right|}}=B
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="66" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img90.png"
ALT="$\displaystyle {\ensuremath{\left\vert{B_\ell}\right\vert}}=B$">
</DIV><P>
</P>
and each centered in
<P><!-- MATH
\begin{displaymath}
\hat{B}_\ell={\ensuremath{{2\theta}}}_0+(\ell-1/2)B,
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="166" HEIGHT="38" ALIGN="MIDDLE" BORDER="0"
SRC="img91.png"
ALT="$\displaystyle \hat{B}_\ell={\ensuremath{{2\theta}}}_0+(\ell-1/2)B,$">
</DIV><P>
</P>
covering completely the angular range between <!-- MATH
${\ensuremath{{2\theta}}}_0$
-->
<IMG
WIDTH="28" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img92.png"
ALT="$ {\ensuremath{{2\theta}}}_0$">
and <!-- MATH
${\ensuremath{{2\theta}}}_{max}={\ensuremath{{2\theta}}}_0+MB$
-->
<IMG
WIDTH="140" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img93.png"
ALT="$ {\ensuremath{{2\theta}}}_{max}={\ensuremath{{2\theta}}}_0+MB$">
.
</DD>
<DT>4. </DT>
<DD>
For bin <IMG
WIDTH="11" HEIGHT="15" ALIGN="BOTTOM" BORDER="0"
SRC="img94.png"
ALT="$ \ell$">
, we consider only and all the experimental intervals
<P><!-- MATH
\begin{displaymath}
b_{k,j}\qquad\text{such\ that}\qquad {\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}} > 0.
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="29" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img95.png"
ALT="$\displaystyle b_{k,j}$">&nbsp; &nbsp;such that<IMG
WIDTH="139" HEIGHT="32" ALIGN="MIDDLE" BORDER="0"
SRC="img96.png"
ALT="$\displaystyle \qquad {\ensuremath{\left\vert{ b_{k,j}\cap B_\ell }\right\vert}} &gt; 0.
$">
</DIV><P>
</P>
More restrictively, one may require to consider only and all the experimental intervals
<P><!-- MATH
\begin{displaymath}
b_{k,j}\qquad\text{such\ that}\qquad \hat{b}_{k,j}\in B_\ell .
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="29" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img95.png"
ALT="$\displaystyle b_{k,j}$">&nbsp; &nbsp;such that<IMG
WIDTH="103" HEIGHT="40" ALIGN="MIDDLE" BORDER="0"
SRC="img97.png"
ALT="$\displaystyle \qquad \hat{b}_{k,j}\in B_\ell .
$">
</DIV><P>
</P>
</DD>
<DT>5. </DT>
<DD>
In order to estimate the rate in each <IMG
WIDTH="11" HEIGHT="15" ALIGN="BOTTOM" BORDER="0"
SRC="img94.png"
ALT="$ \ell$">
-th bin,
we use all above selected rate estimates concerning bin <IMG
WIDTH="23" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img98.png"
ALT="$ B_\ell$">
and we get
a better one with the weighted average method.
<BR>
In the weighted average method, we suppose to have a number <IMG
WIDTH="28" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img99.png"
ALT="$ N_E$">
of estimates <IMG
WIDTH="25" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img100.png"
ALT="$ O_n$">
of the same observable <IMG
WIDTH="17" HEIGHT="15" ALIGN="BOTTOM" BORDER="0"
SRC="img101.png"
ALT="$ O$">
,
each one with a known s.d. <!-- MATH
$\sigma_{O_n}$
-->
<IMG
WIDTH="32" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img102.png"
ALT="$ \sigma_{O_n}$">
and each (optionally) repeated with a frequency
<IMG
WIDTH="21" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img103.png"
ALT="$ \nu_n$">
.
Then
<P><!-- MATH
\begin{displaymath}
\langle O\rangle ={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{
\mathop{\sum}_{n=1}^{N_E}\nu_n
O_n\sigma_{O_n}^{-2}
}}}}{{\ensuremath{\displaystyle{
\mathop{\sum}_{n=1}^{N_E}\nu_n
\sigma_{O_n}^{-2}
}}}}}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="146" HEIGHT="121" ALIGN="MIDDLE" BORDER="0"
SRC="img104.png"
ALT="$\displaystyle \langle O\rangle ={\ensuremath{\displaystyle{\frac{{\ensuremath{\...
...remath{\displaystyle{
\mathop{\sum}_{n=1}^{N_E}\nu_n
\sigma_{O_n}^{-2}
}}}}}}}
$">
</DIV><P>
</P>
Clearly the place of the frequencies in our case can be taken by coefficients
<P><!-- MATH
\begin{displaymath}
{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{{\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}}}}}}{{\ensuremath{\displaystyle{B}}}}}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="77" HEIGHT="55" ALIGN="MIDDLE" BORDER="0"
SRC="img105.png"
ALT="$\displaystyle {\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{{\ens...
...ert{ b_{k,j}\cap B_\ell }\right\vert}}}}}}{{\ensuremath{\displaystyle{B}}}}}}}
$">
</DIV><P>
</P>
that weigh the <IMG
WIDTH="28" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img106.png"
ALT="$ k,j$">
-th estimate by its relative extension within bin <IMG
WIDTH="23" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img98.png"
ALT="$ B_\ell$">
.
</DD>
<DT>6. </DT>
<DD>
Now
we can simply accumulate registers
<P><!-- MATH
\begin{displaymath}
X_\ell=\mathop{\sum_{k,j}}_{ {\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}} > 0}
{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{{\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}}}}}}{{\ensuremath{\displaystyle{B}}}}}}}\ r_{k,j}\ {\ensuremath{\left({\sigma_{r_{k,j}}}\right)}}^{-2}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="288" HEIGHT="87" ALIGN="MIDDLE" BORDER="0"
SRC="img107.png"
ALT="$\displaystyle X_\ell=\mathop{\sum_{k,j}}_{ {\ensuremath{\left\vert{ b_{k,j}\cap...
...aystyle{B}}}}}}}\ r_{k,j}\ {\ensuremath{\left({\sigma_{r_{k,j}}}\right)}}^{-2}
$">
</DIV><P>
</P>
and
<P><!-- MATH
\begin{displaymath}
Y_\ell=\mathop{\sum_{k,j}}_{ {\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}} > 0}
{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{{\ensuremath{\left|{ b_{k,j}\cap B_\ell }\right|}}}}}}{{\ensuremath{\displaystyle{B}}}}}}}\ {\ensuremath{\left({\sigma_{r_{k,j}}}\right)}}^{-2}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="254" HEIGHT="87" ALIGN="MIDDLE" BORDER="0"
SRC="img108.png"
ALT="$\displaystyle Y_\ell=\mathop{\sum_{k,j}}_{ {\ensuremath{\left\vert{ b_{k,j}\cap...
...th{\displaystyle{B}}}}}}}\ {\ensuremath{\left({\sigma_{r_{k,j}}}\right)}}^{-2}
$">
</DIV><P>
</P>
so that we can extract an intensity rate estimate (counts per unit diffraction angle and per unit time at constant incident intensity) as
<P><!-- MATH
\begin{displaymath}
R_\ell={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{X_\ell}}}}{{\ensuremath{\displaystyle{Y_\ell}}}}}}};
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="72" HEIGHT="53" ALIGN="MIDDLE" BORDER="0"
SRC="img109.png"
ALT="$\displaystyle R_\ell={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{X_\ell}}}}{{\ensuremath{\displaystyle{Y_\ell}}}}}}};
$">
</DIV><P>
</P>
<P><!-- MATH
\begin{displaymath}
\sigma_{R_\ell}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{1}}}}{{\ensuremath{\displaystyle{\sqrt{Y_\ell}}}}}}}}.
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="90" HEIGHT="50" ALIGN="MIDDLE" BORDER="0"
SRC="img110.png"
ALT="$\displaystyle \sigma_{R_\ell}={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{1}}}}{{\ensuremath{\displaystyle{\sqrt{Y_\ell}}}}}}}}.
$">
</DIV><P>
</P>
Now optionally we can transforms rates in intensities (multiplying
both <IMG
WIDTH="23" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img111.png"
ALT="$ R_\ell$">
and <!-- MATH
$\sigma_{R_\ell}$
-->
<IMG
WIDTH="30" HEIGHT="30" ALIGN="MIDDLE" BORDER="0"
SRC="img112.png"
ALT="$ \sigma_{R_\ell}$">
by <IMG
WIDTH="17" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img113.png"
ALT="$ B$">
).
We can use any other scaling factor <IMG
WIDTH="19" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img114.png"
ALT="$ K$">
as we wish instead of <IMG
WIDTH="17" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img113.png"
ALT="$ B$">
.
The best cosmetic scaling is the one where
<P><!-- MATH
\begin{displaymath}
\mathop{\sum}_{\ell=1}^M{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{KR_\ell}}}}{{\ensuremath{\displaystyle{K^2\sigma_{R_\ell}^2}}}}}}}=
{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{1}}}}{{\ensuremath{\displaystyle{K}}}}}}}
\mathop{\sum}_{\ell=1}^M{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{R_\ell}}}}{{\ensuremath{\displaystyle{\sigma_{R_\ell}^2}}}}}}}=M
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="216" HEIGHT="68" ALIGN="MIDDLE" BORDER="0"
SRC="img115.png"
ALT="$\displaystyle \mathop{\sum}_{\ell=1}^M{\ensuremath{\displaystyle{\frac{{\ensure...
...\displaystyle{R_\ell}}}}{{\ensuremath{\displaystyle{\sigma_{R_\ell}^2}}}}}}}=M
$">
</DIV><P>
</P>
as if the intensities were simply counts.
Therefore <IMG
WIDTH="19" HEIGHT="14" ALIGN="BOTTOM" BORDER="0"
SRC="img114.png"
ALT="$ K$">
is given by
<P><!-- MATH
\begin{displaymath}
K={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{
1
}}}}{{\ensuremath{\displaystyle{
M
}}}}}}}\mathop{\sum}_{\ell=1}^M{\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{R_\ell}}}}{{\ensuremath{\displaystyle{\sigma_{R_\ell}^2}}}}}}}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="119" HEIGHT="68" ALIGN="MIDDLE" BORDER="0"
SRC="img116.png"
ALT="$\displaystyle K={\ensuremath{\displaystyle{\frac{{\ensuremath{\displaystyle{
1
...
...h{\displaystyle{R_\ell}}}}{{\ensuremath{\displaystyle{\sigma_{R_\ell}^2}}}}}}}
$">
</DIV><P>
</P>
<P>
In output then we give 3-column files
with columns
<P><!-- MATH
\begin{displaymath}
\hat{B}_\ell, \quad KR_\ell, \quad K\sigma_{R_\ell}
\end{displaymath}
-->
</P>
<DIV ALIGN="CENTER">
<IMG
WIDTH="141" HEIGHT="38" ALIGN="MIDDLE" BORDER="0"
SRC="img117.png"
ALT="$\displaystyle \hat{B}_\ell, \quad KR_\ell, \quad K\sigma_{R_\ell}
$">
</DIV><P>
</P>
</DD>
</DL>
<P>
<BR><HR>
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<ADDRESS>
Thattil Dhanya
2018-09-28
</ADDRESS>
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