consistent use of ssize_t instead of int64_t (#167)
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- Consistent use of ssize_t to avoid issues on 32 bit platforms and also
mac with (long long int as ssize_t)
This commit is contained in:
Erik Fröjdh
2025-04-25 15:52:02 +02:00
committed by GitHub
parent 6db201f397
commit 12ae1424fb
16 changed files with 118 additions and 116 deletions
+10 -10
View File
@@ -44,9 +44,9 @@ TEST_CASE("3D NDArray from NDView"){
REQUIRE(image.size() == view.size());
REQUIRE(image.data() != view.data());
for(int64_t i=0; i<image.shape(0); i++){
for(int64_t j=0; j<image.shape(1); j++){
for(int64_t k=0; k<image.shape(2); k++){
for(ssize_t i=0; i<image.shape(0); i++){
for(ssize_t j=0; j<image.shape(1); j++){
for(ssize_t k=0; k<image.shape(2); k++){
REQUIRE(image(i, j, k) == view(i, j, k));
}
}
@@ -54,7 +54,7 @@ TEST_CASE("3D NDArray from NDView"){
}
TEST_CASE("1D image") {
std::array<int64_t, 1> shape{{20}};
std::array<ssize_t, 1> shape{{20}};
NDArray<short, 1> img(shape, 3);
REQUIRE(img.size() == 20);
REQUIRE(img(5) == 3);
@@ -71,7 +71,7 @@ TEST_CASE("Accessing a const object") {
}
TEST_CASE("Indexing of a 2D image") {
std::array<int64_t, 2> shape{{3, 7}};
std::array<ssize_t, 2> shape{{3, 7}};
NDArray<long> img(shape, 5);
for (uint32_t i = 0; i != img.size(); ++i) {
REQUIRE(img(i) == 5);
@@ -114,7 +114,7 @@ TEST_CASE("Divide double by int") {
}
TEST_CASE("Elementwise multiplication of 3D image") {
std::array<int64_t, 3> shape{3, 4, 2};
std::array<ssize_t, 3> shape{3, 4, 2};
NDArray<double, 3> a{shape};
NDArray<double, 3> b{shape};
for (uint32_t i = 0; i != a.size(); ++i) {
@@ -179,9 +179,9 @@ TEST_CASE("Compare two images") {
}
TEST_CASE("Size and shape matches") {
int64_t w = 15;
int64_t h = 75;
std::array<int64_t, 2> shape{w, h};
ssize_t w = 15;
ssize_t h = 75;
std::array<ssize_t, 2> shape{w, h};
NDArray<double> a{shape};
REQUIRE(a.size() == w * h);
REQUIRE(a.shape() == shape);
@@ -224,7 +224,7 @@ TEST_CASE("Bitwise and on data") {
TEST_CASE("Elementwise operations on images") {
std::array<int64_t, 2> shape{5, 5};
std::array<ssize_t, 2> shape{5, 5};
double a_val = 3.0;
double b_val = 8.0;